Chapter 5. Glencoe Algebra 2. Chapter 5 Review Worksheet ... Estimate the x- coordinate at which the relative maxima and minima occur. 1. f(x) = â...

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Chapter 5 Review Worksheet Graph the function. Estimate the x-coordinates of each real zero. Estimate the xcoordinate at which the relative maxima and minima occur. 1. f(x) = 𝑥 ! – 3x + 1 x

f(x)

–3 –2 –1 0 1 2 3

For Questions 2-6, use the graph shown at the right. 2. Determine the values of x between which a real zero is located. A between –1 and 0 B between 6 and 7 C between –2 and –1 D between 2 and 3 3. Estimate the x-coordinate at which a relative minimum occurs. A0 B -1,2 C2 D -∞ 4. Describe the end behavior of the graph. A as x→ −∞, 𝑓 𝑥 → ∞ B as x→ −∞, 𝑓 𝑥 → −∞ as x→ ∞, 𝑓 𝑥 → ∞ as x→ ∞, 𝑓 𝑥 → −∞ C as x→ −∞, 𝑓 𝑥 → ∞ as x→ ∞, 𝑓 𝑥 → −∞ 5. State the number of real zeros. A1 B 2 C 3

D as x→ −∞, 𝑓 𝑥 → −∞ as x→ ∞, 𝑓 𝑥 → ∞

D none

6. Determine whether the graph represents an odd-degree or an even-degree polynomial function. What is the degree of this function? A odd; 1 B odd; 3 C even; 2 D even; 4

Chapter 5

Glencoe Algebra 2

NAME ____________________________________________ DATE ____________________________ PERIOD _____________

7. Simplify (𝑥 ! – 2x – 35) ÷ (x + 5). F 𝑥 ! – x – 30 Gx+5

Hx–7 J 𝑥 ! + 3𝑥 ! – 45x – 175

8. Factor 𝑚 ! – 7m2 + 18 completely. F (m + 2)(m – 9) G (m2 + 2) (m + 3) (m – 3)

H (m2 + 2)(m2 – 9) J prime

9. State the number of real zeros for the function whose graph is shown at the right. A0 C2 B1 D3

10. Solve 𝑥 ! – 13𝑥 ! + 36 = 0. A –3, –2, 2, 3 B –9, –4, 4, 9

Answers:

C 2, 3, 2i, 3i

D –2, –3, 2i, 3i

2. C 3. C

11. One factor of 𝑥 ! + 4𝑥 ! – 11x – 30 is x + 2. Find the remaining factors. A x – 5, x + 3 B x – 3, x + 5 C x – 6, x + 5 D x – 5, x + 6

4. D

– 12. Factor 8𝑥 ! – 125𝑦 ! A (2x – 5y)(4x2 + 10xy – 25y2) C (2x + 5y)(4x2 – 10xy + 25y2)

6. B B (2x – 5y)(4x2 + 10xy + 25y2) D (8x – 125y)(64x2 + 1000x + 15,635)

5. A

7. H 8. G 9.

−2

13.

14.

2

y2 A 2 x

" x 2 % " y2 % $ −1 ' $ −1 ' #y & #x & 1 B x2

Simplify:

4x3y-6 + (x-1y2) -3

4x 6 A 12 y

5 B 3 6 x y

Simplify:

A

10. A 2 2

C x y

11. B

y2 D x6

12. B 13. A 14. C

5x 3 C y6

3 6

D 5x y

15. C

15. Find the value of k so that x – 3 divides into 2x3 – 11x + k with no remainder. A -15 Chapter 5

B 15

C -21

D 21 Glencoe Algebra 2