3. SOLUTION: Factor the perfect square trinomial. Use the Square Root Property. The solution set is {â12.87, â5.13}. 5. LASER LIGHT SHOW The area ...
4-5 Completing the Square Solve each equation by using the Square Root Property. Round to the nearest hundredth if necessary.
1.
SOLUTION:
Factor the perfect square trinomial.
Use the Square Root Property.
The solution set is {–8.45, –3.55}.
3.
SOLUTION:
Factor the perfect square trinomial.
Use the Square Root Property.
The solution set is {–12.87, –5.13}.
2
5. LASER LIGHT SHOW The area A in square feet of a projected laser light show is given by A = 0.16d , where d is the distance from the laser to the screen in feet. At what distance will the projected laser light show have an area of 100 square feet?by Cognero eSolutions Manual - Powered Page 1
SOLUTION:
The solution set {–12.87, –5.13}. 4-5 Completing theisSquare
2
5. LASER LIGHT SHOW The area A in square feet of a projected laser light show is given by A = 0.16d , where d is the distance from the laser to the screen in feet. At what distance will the projected laser light show have an area of 100 square feet?
SOLUTION: Substitute 100 for A, and find the value of d.
Use the Square Root Property.
d cannot be negative.
So, the distance is 25 feet. Find the value of c that makes each trinomial a perfect square. Then write the trinomial as a perfect square.
7.
SOLUTION: To find the value of c, divide the coefficient of x by 2 and square the result. So: c = 6.25 Substitute 6.25 for c in the trinomial.
Solve each equation by completing the square.
9.
SOLUTION:
Use the Square Root Property.
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Substitute 6.25 for c in the trinomial.
4-5 Completing the Square Solve each equation by completing the square.
9.
SOLUTION:
Use the Square Root Property.
The solution set is
.
11.
SOLUTION:
Use the Square Root Property.
The solution set is { –4.37, 1.37}.
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13.
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4-5 Completing The solution the set isSquare { –4.37, 1.37}.
13.
SOLUTION:
Use the Square Root Property.
Solve each equation by using the Square Root Property. Round to the nearest hundredth if necessary.
15.
SOLUTION:
Use the Square Root Property.
17.
SOLUTION:
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The solution set is {–7.65, –2.35}.
Page 4
4-5 Completing the Square 17.
SOLUTION:
The solution set is {–7.65, –2.35}.
19.
SOLUTION:
Use the Square Root Property.
The solution set is {–1, 3}.
21.
SOLUTION:
Use the Square Root Property.
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The solution set is {4.67, 10.33}.
Page 5
The solution set {–1, 3}. 4-5 Completing theisSquare
21.
SOLUTION:
Use the Square Root Property.
The solution set is {4.67, 10.33}.
23.
SOLUTION:
Use the Square Root Property.
The solution set is {–0.95, 3.95}
25.
SOLUTION:
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Use the Square Root Property.
Page 6
The solution set {–0.95, 3.95} 4-5 Completing theisSquare