Name ________________________________________ Date __________________ Class __________________ LESSON
15-4
Segment Relationships in Circles Practice and Problem Solving: A/B
For each figure, determine the value of the variable and the indicated lengths by applying the Chord-Chord Product Theorem. 1.
3.
x=
2.
y=
AD =
FH =
BE =
GI =
z=
4.
m=
PS =
UW =
RT =
VX =
For each figure, determine the value of the variable and the indicated lengths by applying the Secant-Secant Product Theorem. 5.
7.
x=
6.
y=
BD =
GJ =
FD =
GK =
z=
8.
n=
SQ =
CE =
SU =
CF =
For each figure, determine the value of the variable and the indicated length by applying the Secant-Tangent Product Theorem. 9.
x=
10.
IK =
y= KM =
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300
12. 4(x + 4) = 64
LESSON 15-4
13. 12
Practice and Problem Solving: A/B
14. 16
1. x = 1, AD = 6, BE = 9
Reading Strategies
2. y = 7, FH = 8.3, GI = 9.4
1. 2.5
3. z = 7, PS = 9.4, RT = 9.4
2. 8
4. m = 4.5, UW = 8.5, VX = 9.4
3. 8
5. x = 4.5, BD = 9.5, FD = 9.5
4. 16
6. y = 11.5, GJ = 21, GK = 17.5
5. 7
7. z = 19, SQ = 18, GK = 28
6. 24
8. n = 8.25, CE = 20.25, CF = 27
Success for English Learners
9. x = 1.5, IK = 2
1. No; there may be several factors for the lengths of the chords. You would have to know at least the length of one segment of each chord.
100 10. y = 10, KM = 7
Practice and Problem Solving: C
2. No; the angles do not affect the length of the chords or the segments in this situation and have no influence in using the Chord-Chord Product Theorem.
1. x = 2 2. x = 4 11 3. x =
174 − 6
4. x =
366 − 5 2
5. x =
14 − 2 2
LESSON 15-5 Practice and Problem Solving: A/B 1. m∠RPS = 130° 2. m∠YUV = 81°
6. x = 2 35 − 2 3
3. m∠ABE = 64°, m∠ CE = 136°
7. AC = 16.5, BD = 16.8
4. m∠LKI = 119°, m∠ IJ = 42°
8. PY = 40.5
5. x = 64 6. x = 47
Practice and Problem Solving: Modified
7. x = 45
1. JN i LN = KN i MN
8. x = 8
2. 10x = 60
9. m YZ = 120°
3. x = 6
10. m DE = 80°
4. JL = 16
Practice and Problem Solving: C
5. KM = 17
1. m∠DEI = 66.5°, m∠ EF = 115°
6. TV i UV = XV i WV
2. m∠WVR = 84°, m∠ TUW = 92°
7. 44 = 5(a + 5)
3. Possible answer: It is given that AB ≅ EB. So ABC is isosceles and ∠BAE ≅ ∠BEA. Since ∠BEC is an 1 inscribed angle, m∠BEC = BC. By 2
8. a = 3.8 9. TV = 11 10. XV = 8.8 11. HJ i IJ = KJ2
Original content Copyright © by Houghton Mifflin Harcourt. Additions and changes to the original content are the responsibility of the instructor.
519